A dielectric material is to fill the space in a capacitor Initially, with only air in place, the capacitance is `8.0 mu F` With the dielectric material in place, the capacitor should store `3.2 mu J` at a maximum potential difference of 350.8V. (a) What dielectric constant is required? (b) Of the materials in Table 25-1, which material should be used?

Explanation

To solve the problem step by step, we will follow these calculations:

### Given Data:
- Initial capacitance (C₀) = 8.0 µF = 8.0 × 10⁻⁶ F
- Energy stored (U) = 3.2 µJ = 3.2 × 10⁻⁶ J
- Maximum potential difference (V) = 350.8 V

### Step 1: Calculate the new capacitance (C) using the energy formula.
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