The parallel plates in a capacitor, with a plate area of `8.50 cm^2` and an air filled separation of 8.00 mm are charged by a 16.0 battery . Then are then disconnected from the battery and pushed together (without discharge) to a separation of 3.00 mm. Neglecting fringing the (a) the potential difference between the plates (b) the initial stored energy (c ) the final stored energy and (d) the (negative) work is pushing them together.

Explanation

To solve the problem step by step, we will calculate the required values for the parallel plate capacitor as described in the question.

### Given Data:
- Plate area, \( A = 8.50 \, \text{cm}^2 = 8.50 \times 10^{-4} \, \text{m}^2 \)
- Initial separation, \( d_1 = 8.00 \, \text{mm} = 8.00 \times 10^{-3} \, \text{m} \)
- Final separation, \( d_2 = 3.00 \, \text{mm} = 3.00 \times 10^{-3} \, \text{m} \)
- Voltage from the battery, \( V = 16.0 \, \text{V} \)
- Permittivity of free space, \( \epsilon_0 = 8.85 \times 10^{-12} \, \text{F/m} \)
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