A certan substance has a dielectric constant of 5.6 and a dielectric strength of `18 mV//m` . IF it is used as the dielectric material in a parallel plate capacitor. What minium area should the plates of the capacitor have to obtain a capacitance of `3.9 times 10^-2 mu F` and to ensure that the capacitor will be able to withstand a potential difference of 4.0 kV?

Explanation

To solve the problem, we need to find the minimum area of the plates of a parallel plate capacitor that can achieve a specified capacitance while also being able to withstand a certain voltage without breaking down. Here's the step-by-step solution:

### Step 1: Understand the given values
- Dielectric constant (K) = 5.6
- Dielectric strength (E) = 18 mV/m = 18 × 10^-3 V/m
- Desired capacitance (C) = 3.9 × 10^-2 µF = 3.9 × 10^-8 F
- Voltage (V) = 4.0 kV = 4.0 × 10^3 V

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