You have two flat metal plates, each of area `1.00 m^2` with which to construct a parallel plate capacitor (a) If the capacitance of the device is to be 2.00F what must be the separation between the plates? (b) could this capacitor actually be constructed?

Explanation

To solve the problem step-by-step, we will use the formula for the capacitance of a parallel plate capacitor, which is given by:

\[ C = \frac{\varepsilon_0 A}{d} \]

where:
- \( C \) is the capacitance,
- \( \varepsilon_0 \) is the permittivity of free space (\( \varepsilon_0 \approx 8.85 \times 10^{-12} \, \text{F/m} \)),
- \( A \) is the area of one of the plates,
...