The emf and resistances in the circuit of Fig 27-8a have the following values:
`epsi_(1)=4.4 V. epsi_(2)=2.1V`,
`r_(1)=2.3 Omega, r_(2)=1.8 Omega, R=5.5 Omega`
(a) What is the current I in the circuit?
(b) What is the potential difference between the terminals of battery 1 in Fig. 27 8a?

Explanation

To solve the problem step-by-step, we will first find the current \( I \) in the circuit and then determine the potential difference between the terminals of battery 1.

### Step 1: Identify the circuit components and values
We have the following values given:
- EMF of battery 1, \( \epsilon_1 = 4.4 \, V \)
- EMF of battery 2, \( \epsilon_2 = 2.1 \, V \)
- Internal resistance of battery 1, \( r_1 = 2.3 \, \Omega \)
- Internal resistance of battery 2, \( r_2 = 1.8 \, \Omega \)
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