A 1.5 `muF` capacitor is charged to 57 V. The charging battery is then disconnected , and a 12 mH coil is connected in series with the capacitor so that LC oscillations occur. What is the maximum current in the coil ? Assume that the circuit contains no resistance , which woudl cause the energy to be dissipated.

Explanation

To find the maximum current in the coil when a charged capacitor is connected to an inductor, we can follow these steps:

### Step 1: Calculate the Energy Stored in the Capacitor
The energy (U) stored in a capacitor is given by the formula:
\[ U = \frac{1}{2} C V^2 \]
where:
- \( C \) is the capacitance in farads,
- \( V \) is the voltage in volts.
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