Once the electron has been exicted to the second excited state, what wavelengths of light can it emit by de - excitation?

Explanation

To determine the wavelengths of light that can be emitted when an electron in a hydrogen atom de-excites from the second excited state (n=3), we need to consider the possible transitions the electron can make. The electron can transition from n=3 to n=2, n=3 to n=1, and n=2 to n=1. We will calculate the wavelengths for each of these transitions using the Rydberg formula.

### Step-by-Step Solution:

1. **Identify the Energy Levels**:
- The electron is in the second excited state, which corresponds to n=3.
- The possible transitions are:
- From n=3 to n=2
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