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According to Bohr's theory, the variatio...

According to Bohr's theory, the variation of perimeter(s) of the electronic orbit with the order of orbit (n) in a particular atom is

A

Linear

B

Parabolic

C

Exponential

D

Rectangular hyperbolic

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The correct Answer is:
To solve the problem of how the perimeter of the electronic orbit varies with the order of the orbit (n) according to Bohr's theory, we can follow these steps: ### Step 1: Understand the Concept of Perimeter The perimeter of an electronic orbit in an atom is essentially the circumference of the circular orbit. The formula for the circumference (perimeter) of a circle is given by: \[ \text{Perimeter} = 2\pi r \] where \( r \) is the radius of the orbit. **Hint:** Remember that the perimeter of a circle is directly related to its radius. ### Step 2: Relate the Radius to the Principal Quantum Number (n) According to Bohr's theory, the radius of the nth orbit (denoted as \( R_n \)) is given by the formula: \[ R_n = \frac{n^2}{Z} \cdot a_0 \] where: - \( n \) is the principal quantum number, - \( Z \) is the atomic number, - \( a_0 \) is the Bohr radius (approximately \( 0.529 \, \text{Å} \)). **Hint:** The radius increases with the square of the principal quantum number. ### Step 3: Substitute the Radius into the Perimeter Formula Substituting the expression for \( R_n \) into the perimeter formula, we get: \[ \text{Perimeter} = 2\pi R_n = 2\pi \left(\frac{n^2}{Z} \cdot a_0\right) \] This simplifies to: \[ \text{Perimeter} = \frac{2\pi a_0}{Z} \cdot n^2 \] **Hint:** Notice that the perimeter is proportional to \( n^2 \). ### Step 4: Identify the Variation Type From the equation \( \text{Perimeter} = k \cdot n^2 \) (where \( k = \frac{2\pi a_0}{Z} \)), we can see that the perimeter varies with the square of the principal quantum number \( n \). This indicates a parabolic relationship. **Hint:** A relationship of the form \( y = kx^2 \) represents a parabolic variation. ### Conclusion Thus, according to Bohr's theory, the variation of the perimeter of the electronic orbit with the order of the orbit \( n \) is parabolic. **Final Answer:** The perimeter varies parabolically with the order of the orbit \( n \). ---
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