An electron in a mercury atoms is in the 3d subshell. Which of the following `m_(l)` values are possible for it, (a) `-3`, (b) `-1`, (c ) 0, (d) 1, (e) 2?

Explanation

To determine the possible values of \( m_l \) for an electron in the 3d subshell of a mercury atom, we can follow these steps:

### Step 1: Identify the Principal Quantum Number (n)
The electron is in the 3d subshell, which indicates that the principal quantum number \( n \) is 3.

### Step 2: Identify the Azimuthal Quantum Number (l)
For the d subshell, the azimuthal quantum number \( l \) is 2. The values of \( l \) for different subshells are as follows:
- s subshell: \( l = 0 \)
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