A high-powered laser beam `(lambda=600nm)` with a beam diameter of 10 cm is aimed at the Moon, `3.8xx10^(5)km` distant. The beam spreads only because of diffraction. The angular location of the edge of the central diffraction disk is given by
`sintheta=(1.22lambda)/(d)`,
where d is the diameter of the beam aperture. What is the diameter of the central diffraction disk on the Moon's surface?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Convert the given values to SI units
- Wavelength, \( \lambda = 600 \, \text{nm} = 600 \times 10^{-9} \, \text{m} \)
- Diameter of the beam, \( d = 10 \, \text{cm} = 0.1 \, \text{m} \)
- Distance to the Moon, \( D = 3.8 \times 10^5 \, \text{km} = 3.8 \times 10^8 \, \text{m} \)

### Step 2: Calculate \( \sin \theta \) using the given formula
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