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Electrons with de-Broglie wavelength lam...

Electrons with de-Broglie wavelength `lambda` fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

A

`lambda_(0)=(2mclambda^(2))/(h)`

B

`lambda_(0)=(2h)/(mc)`

C

`lambda_(0)=(2m^(2)c^(2)lambda^(3))/(h^(2))`

D

`lambda_(0)=lambda`

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The correct Answer is:
A
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