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The spin angular momentum of an electron...

The spin angular momentum of an electron is equal to

A

`sqrt(3)`

B

`hsqrt(3)//4pi`

C

`h//2`

D

`pmh//2`

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The correct Answer is:
To find the spin angular momentum of an electron, we can follow these steps: ### Step 1: Understand the concept of spin angular momentum The spin angular momentum of a particle is a fundamental property, similar to its mass or charge. For electrons, the intrinsic spin quantum number \( s \) is equal to \( \frac{1}{2} \). ### Step 2: Use the formula for spin angular momentum The formula for the magnitude of the spin angular momentum \( L \) is given by: \[ L = \sqrt{s(s + 1)} \hbar \] where \( \hbar \) is the reduced Planck's constant, defined as \( \hbar = \frac{h}{2\pi} \). ### Step 3: Substitute the value of \( s \) For an electron, we substitute \( s = \frac{1}{2} \) into the formula: \[ L = \sqrt{\frac{1}{2} \left(\frac{1}{2} + 1\right)} \hbar \] ### Step 4: Simplify the expression Now, simplify the expression inside the square root: \[ L = \sqrt{\frac{1}{2} \left(\frac{3}{2}\right)} \hbar = \sqrt{\frac{3}{4}} \hbar \] ### Step 5: Finalize the expression Thus, the spin angular momentum of an electron can be expressed as: \[ L = \frac{\sqrt{3}}{2} \hbar \] ### Conclusion The spin angular momentum of an electron is \( \frac{\sqrt{3}}{2} \hbar \). ---
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