Home
Class 12
PHYSICS
U^238 decays into Th^234 by the emission...

`U^238` decays into `Th^234` by the emission of an a-particle. There follows a chain of further radioactive decays, either by `alpha`-decay or by `beta-`decay. Eventually a stable nuclide is reached and after that, no further radioactive decay is possible. which of the following stable nuclides is the end product of the `U^238` radioactive decay chain ?

Text Solution

Verified by Experts

The correct Answer is:
`""^(206)Pb`
Promotional Banner

Topper's Solved these Questions

  • THE NUCLEUS

    RESNICK AND HALLIDAY|Exercise PROBLEMS|66 Videos

  • THE NUCLEUS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Single Correct Choice Type)|69 Videos

  • THE NUCLEUS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS(Integer Type)|7 Videos

  • THE KINETIC THEORY OF GASES

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS|72 Videos

  • UNITS AND MEASUREMENT

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (MATRIX-MATCH)|11 Videos

Similar Questions

Explore conceptually related problems

Which of the following are mode of radioactive decay ?

In radioactive decay, which one of the following moves the fastest ?

Which one of the following is not a mode of radioactive decay?

Carbon-14 radioactively decays via the emission of a beta particle. Which of the following is the product of this decay?

The decay constant of the end product of a radioactive series is

Radioactive decay follows which order kinetics?

A radioactive decay can form an isotope of the original nucleus with the emission of particles