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The radionuclide .6C^(11) decays accordi...

The radionuclide `._6C^(11)` decays according to `._6C^(11)to ._5B^(11) +e^(+) +v`: half life =20.3min. The maximum energy of the emitted positron is `0.960 MeV`. Given the mass values
`m(._6C^(11))=11.011434u, m(._6B^(11))=11.009305u`
Calculate Q and compare it with maximum energy of positron emitted.

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The correct Answer is:
b. 0.961MeV
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