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In a radioactive material the activity a...

In a radioactive material the activity at time `t_(1)` is `R_(1)` and at a later time `t_(2)`, it is `R_(2)`. If the decay constant of the material is `lambda`, then

A

`R_(1)=(R_(2)(t_(2)//t_(1))`

B

`R_(1)=R_(2)`

C

`R_(1)=R_(2)e^(-(t_(1)-t_(2)))`

D

`R_(1)=R_(2)e^((t_(1)-t_(2)))`

Text Solution

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The correct Answer is:
C
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