Home
Class 12
PHYSICS
In Rutherford's famous gold foil scatter...

In Rutherford's famous gold foil scatterig experiment he found that most alpha particles would pass throught the foil undeflected. Which of the following nuclear properties can be inferred from this obsevation?

A

Most of the space inside the atom is void

B

Most of the mass of an atom is in the nucleus

C

The nucleus contains both protons and neutrons

D

The diameter of the nucleus is small compared to the diameter of the atom.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding Rutherford's gold foil scattering experiment and the properties of the nucleus that can be inferred from it, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Experiment**: - Rutherford directed alpha particles at a thin gold foil. He expected that the alpha particles would be deflected due to the positive charge spread throughout the atom (as per Thomson's model). 2. **Observation of Alpha Particle Behavior**: - Most of the alpha particles passed through the foil undeflected, with only a small fraction being deflected at large angles. This indicated that the majority of the atom is not dense. 3. **Inference About Atomic Structure**: - Since most alpha particles passed through without deflection, it can be inferred that most of the space within the atom is empty. This suggests that the positive charge and mass are concentrated in a very small region (the nucleus). 4. **Conclusion About Nuclear Properties**: - The main conclusion drawn from this observation is that "most of the space inside the atom is void." This means that the atom consists mostly of empty space, with a small, dense nucleus at its center. 5. **Other Properties**: - Although Rutherford's experiment also led to the understanding that the nucleus contains protons and neutrons and that the nucleus is small compared to the overall size of the atom, these specific details were not directly inferred from the observation of undeflected alpha particles. ### Final Answer: From Rutherford's gold foil experiment, we can infer that **most of the space inside the atom is void**. ---
Promotional Banner

Topper's Solved these Questions

  • THE NUCLEUS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (More than One Correct Choice Type)|22 Videos
  • THE NUCLEUS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Linked Comprehension)|12 Videos
  • THE NUCLEUS

    RESNICK AND HALLIDAY|Exercise PROBLEMS|66 Videos
  • THE KINETIC THEORY OF GASES

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS|72 Videos
  • UNITS AND MEASUREMENT

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (MATRIX-MATCH)|11 Videos

Similar Questions

Explore conceptually related problems

In Rutherford's gold foil experiment, the scattering of alpha -particles takes place. In this process:

Most of the alpha -particles passed through the foil undeviated . What can be concluded from this observation ?

In Rutherford's gold foil experiment most of the alpha -particles pass through the gold foil without any deviation from their paths . This indicates that

Rutherford's alpha particle scattering experiment on thin gold foil was responsible for the discovery of

Most of the alpha -particles passed straight through the gold foil. This proved the existence of in an atom.

In interperting Rutherford's experiments on the scattering of alpha particle by thin foils, one must examine what were known factors, and what the experiment settle. Which of the following are true in this context?

At the suggestion of Earnest Rutherford, hans Geiger and ernest Marsden bombarded a thin gold foil by alpha -particles from a polonium source. It was expected that alpha -particles would go right through the foil with hardly any deflection. Although, most of the alpha particles indeed were not deviated by much, a few were scattered through veryi large angles. Some were even scattered in the backward direction. The nly way to explain the results, rutherford found, was to picture an atom as being compoed of a tiny nucleus in which its positive charge and nearly all its mass are concentrated. Scattering of alpha -particles is proportional to target thickness and is inversely proportional to the fourth power of sin((theta)/(2)) , where, theta is scattering angle. Distance of closest approach may be calculated as: r_("min")=(Z_(1)Z_(2)e^(2))/(4piepsi_(0)K) where, K=kinetic energy of alpha -particles. Q. Rutherford's alpha -particle scattering led to the conclusion that:

RESNICK AND HALLIDAY-THE NUCLEUS-PRACTICE QUESTIONS (Single Correct Choice Type)
  1. The atomic mass of B^(10) is 10.811 amu . Find the binding energy of B...

    Text Solution

    |

  2. Four vessels A,B,C and D respectively, contains 20 g atom (T(1//2=5h),...

    Text Solution

    |

  3. In Rutherford's famous gold foil scatterig experiment he found that mo...

    Text Solution

    |

  4. The electron, neutron, and proton, listed in descending order of mass ...

    Text Solution

    |

  5. Which of the following is a wrong description of binding energy of a n...

    Text Solution

    |

  6. The binding energies of the atoms of elements A and B are E(a) and E(b...

    Text Solution

    |

  7. How does the rest energy of a nucleus compare to the sum of the rest e...

    Text Solution

    |

  8. The binding energies of the nuclei of .2^4 He, .3^7 Li, .6^12 C and .7...

    Text Solution

    |

  9. In the nuclear reaction descried by the equation below, an alpha parti...

    Text Solution

    |

  10. Nucleus A is converted into C through the following reactions, ArarrB...

    Text Solution

    |

  11. In one average life (assuming the decay to proceed according to radioa...

    Text Solution

    |

  12. 90% of the active nuclei present in a radioactive sample are found to ...

    Text Solution

    |

  13. Let T be the mean life of a radioactive sample. 75% of the active nucl...

    Text Solution

    |

  14. A freshly prepared radioactive source of half-life 2 h emits radiation...

    Text Solution

    |

  15. The half life of .^(131)I is 8day. Given a sample of .^(131)1 at t = 0...

    Text Solution

    |

  16. A radioactive sample consists of two distinct species having equal num...

    Text Solution

    |

  17. Half-lives of two radioactive elements A and B are 20 minutes and 40 m...

    Text Solution

    |

  18. The ratio of molecular mass of two radioactive substances is 3//2 and ...

    Text Solution

    |

  19. An unstable nucleus decays in three different modes, each mode having ...

    Text Solution

    |

  20. The decay constant of a radioactive material represents the fraction o...

    Text Solution

    |