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Gold nucleus (""(79)^(198)Au) can decay ...

Gold nucleus `(""_(79)^(198)Au)` can decay into mercuyr nucleus `(""_(80)^(198)Hg^(8))` by two decay schemes shown in figure below (i) it can emit a `beta` -particle `(beta_(1))` and come to ground state by either emiting one `gamma`- ray (` gamma_(1)`) or emitting two `gamma`- rays (`gamma_(3)` and `gamma_(4)`) (ii) It can emit one `beta`- particle `(beta_(2))` and come to ground state by emitting `gamma_(2)` ray. Atomic masses: `""^(198)Au=197.9652` amu and `""^(198)Hg=197.9662` amu. Given that 1 amu= `930MeV//c^(2)`. The energy levels of the nucleus are shown in figure below

The wavelength of emitted `gamma` - rays is the order

A

`lamda_(2)gtlamda_(3)gt lamda_(1)`

B

`lamda_(3)gtlamda_(2)gtlamda_(1)`

C

`lamda_(1)gtlamda_(2)gtlamda_(3)`

D

`lamda_(3)=lamda_(2)=lamda_(1)`

Text Solution

Verified by Experts

The correct Answer is:
A
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