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We have two radioactive nuclei A and B. ...

We have two radioactive nuclei `A` and `B`. Both convert into a stable nucleus `C`. Nucleus `A` converts into `C` after emitting two two `alpha`-particles and three `beta`-particles. Nucleus `B` converts into `C` after emitting one.
`alpha`-particle anf five `beta`-particles. A time `t = 0`, nuclei of `A` are `4N_(0)` and that of `B` are `N_(0)`. Half-life of `A`(into the conversion of `C`) is `1min` and that of `B` is `2min`. Initially number of nuclei of `C` are zero.
If atomic numbers and mass numbers of `A` and `B` are `Z_(1),Z_(2),A_(1)` and `A_(2)` respectively. Then

A

`Z_(1)-Z=6`

B

`A_(1)=A_(2)=4`

C

both b and d are correct.

D

both a and c are wrong

Text Solution

Verified by Experts

The correct Answer is:
B
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