The voltmeter shown in fig, reads 6V across the `60 Omega` resistor. Then the resistance of the voltmeter is-

The voltmeter shown in figure reads 18V across the 50(Omega) resistor. Find the resistance of the voltmeter.

The voltmeter shown in figure reads 18V across the 50(Omega) resistor. Find the resistance of the voltmeter.

The voltmeter shown in figure reads 18V across the 50(Omega) resistor. Find the resistance of the voltmeter.

The voltmeter shown in the figure reads 10V across 40 omega . The resistance of voltmeter is

The voltmeter reads 40 V across 60 Omega resistance. The resistance of voltmeter is. .

50 Omega and 100 Omega resistors are connected in series. This connection is connected with a battery of 24 volts. When a voltmeter of 100 Omega resistance is connected across 100 Omega resistor, then the reading of the voltmeter will be

50 Omega and 100 Omega resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of 100 Omega resistance is connected across 100 Omega resistor, then the reading of the voltmeter will be

Two resistors 10Omega and 25Omega are connected in series and the combination is connected across a 25 V source of negligible internal resistance. A voltmeter of resistance 25Omega is connected across the 10Omega resistor. Find the reading in the voltmeter. If another voltmeter of a very large resistance replaces the voltmeter, then find the reading of voltmeter.