" 17."y'''+2y''+y'=0

y" + 2y' + sin y = 0

{:(0.4x + 0.3y = 1.7),(0.7x - 0.2y = 0.8):}

{:(0.4x + 0.3y = 1.7),(0.7x - 0.2y = 0.8):}

y"+(y')^(2) + 2y = 0

I. 3x^(2) - 17x+10 = 0 II. 2y^(2) -5y+3 = 0

The equation of the plane passing through the point (1,1,-1) and perpendicular to the planes x+2y+3z-7=0 and 2x-3y+4z=0 is (a) 17 x+2y-7z=26 (b) 17 x-2y+7z=26 (c) 17 x+2y-7z+26=0 (d) 17 x-2y+7z+26=0

0.4 x + 0.3 y = 1.7 , 0.7 x - 0.2 y = 0.8