[" If a particle of mass "m" moves in a potential energy field "uu=u_(0)-ax+bx^(2)" where "u_(0)," a and "b" are "],[" positive constant.Calculate the force constant,frequency of the particle and point of equilibrium."]

If a particle of mass m moves in a potential energy field U=U_(0)-ax+bx^(2) where U_(0) , a and b are positive constants.Then natural frequency of small oscillations of this particle about stable equilibrium point is (1)/(x pi)sqrt((b)/(m)) . The value of x is?

A particle of mass m moving along x-axis has a potential energy U(x)=a+bx^2 where a and b are positive constant. It will execute simple harmonic motion with a frequency determined by the value of

A particle of mass m moving along x-axis has a potential energy U(x)=a+bx^2 where a and b are positive constant. It will execute simple harmonic motion with a frequency determined by the value of

A particle of mass m moving along x-axis has a potential energy U(x)=a+bx^2 where a and b are positive constant. It will execute simple harmonic motion with a frequency determined by the value of

A particle of mass m moves in a one dimensional potential energy U(x)=-ax^2+bx^4 , where a and b are positive constant. The angular frequency of small oscillation about the minima of the potential energy is equal to

A particle of mass m moves in a one dimensional potential energy U(x)=-ax^2+bx^4 , where a and b are positive constant. The angular frequency of small oscillation about the minima of the potential energy is equal to