(x+iy)(2-3i)=4+i

If (x+iy)(3-4i) = 5+12i , then sqrt(x^2+y^2) =

Express the result in the form x+iy, where x,y are real number i=sqrt(-1) : (i) (2-3i)/(4-i) (ii) (2+3i)/(-5-4i) (iii) (1+i)/(3+i) (iv) (3+2i)/(4-3i)

Express (4+3i)/((2+3i)(4-3i)) in the form of x + iy

Express (2+i)^2/(2+3i) in the form x+iy.

Express (2+i)/(1-3i) is the form x+iy

((x+iy)/(2+3i)+(2+i)/(2-3i)=(9)/(13)(1+i)

Find the values of x and y : (i) x+3i=6-9iy (ii) (x+iy)-(3-2i)=5+i (iii) i=x+2yi (iv) 4x+i(x-y)=2-5i (v) (x+2iy)(2-i)^(2)=10(1-i)

Find the values of x and y : (i) x+3i=6-9iy (ii) (x+iy)-(3-2i)=5+i (iii) i=x+2yi (iv) 4x+i(x-y)=2-5i (v) (x+2iy)(2-i)^(2)=10(1-i)

Write the following in the form x + iy : (3+ 4i)/(2-4i) .