In a triangle ABC, if `(cos A)/(a) =(cos B)/(b ) =(cos C)/(c) ` and the side `a=2,` then the area of the triangle is-

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2

In a triangle ABC, if (cos A)/(a) = (cos B)/(b)= (cos C)/(c ) and a=2 then its area is

If, in triangleABC, (cos A)/a =(cos B)/b =(cos C)/c and side a=2, then the area of the triangle is

in a triangle ABC , ( cos A)/(a) = (cos B )/( b) = ( cos C )/( c ) if a=(1 )/( sqrt(6)) then the area of the triangle ( in square units ) is

In a triangle ABC if (cos A)/a=(cos B)/b= (cos C)/c , then Delta ABC is

If in a triangle ABC, 2 (cos A)/(a) + (cos B)/(b) +2 (cos C)/(c) = (a)/(bc) + b/(ca) then the value of the angle A is

In a triangle ABC, a (b cos C - c cos B) =