EMF of the following cell is 0.6 volt.
`Ag (s) | AgBr ( s) | KBr (0.01 m) |AgNO_(3) ( 0.001M) | Ag( s)`
`K_(sp)` of AgBr is expressed as `1 xx 10^(-x)` , x is [Take `( 2.303RT)/(F ) = 0.06 V ]`

Calculate the emf of the following cell at 25^(@)C Ag(s)|AgNO_(3) (0.01 M)||AgNO_(3) (0.05 M)|Ag (s)

The EMF of the following cell is 0.86 volts Ag|AgNO_(3)(0.0093M)||AgNO_(3)(xM)|Ag . The value of x will be

Calculate the emf of the following concentration cell at 25^(@)C : Ag(s)|AgNO_(3) (0.01 M)||AgNO_(3) (0.05 M)|Ag (s)

Calculate the emf of the following cell at 25^(@)C Ag(s)|AgNO_(3) (0.01" mol "Kg^(-1))| AgNO_(3) ("0.05 mole "Kg^(-1))|Ag(s)

In the following concentration cell Ag(s) // AgCl "(saturated)"// // AgNO_3(aq) (0.1M)//Ag_((s)), K_(SP) " of AgCl"=1 xx 10^(-10) The cell potential will be

For the cell Cu (s) | Cu ^(2+) (aq) (0.1 M) || Ag ^(+) (aq) (0.01 M) | Ag (s) the cell potential E _(1) = 0.3095 V For the cell Cu (s) | Cu ^(+2) (aq) (0.01 M) || Ag ^(+) (aq)( 0. 001 M) | Ag (s) the cell potential = _______ xx 10 ^(-2) V. (Round off the Nearest Integer). [Use : (2.303 RT)/(F) =0.059 ]

AgBr (s) harr Ag^(+) (aq) + Br^(-) (aq); E^(@) = -0.72V If the value of K_(sp) at 25^(@)C is 10^(-b) then the value of "b" is Use (2.303RT)/(F) = 0.06 )