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` sin theta + sin 2 theta + sin 3theta + sin 4 theta =0`

sin theta + sin3 theta + sin5 theta = 0

If sin 6theta = sin 4theta - sin 2theta , then theta =

Solve the following: sin theta + sin 2 theta + sin 3 theta + sin 4 theta=0

sin theta + sin 5 theta = sin 3theta (0 le theta le 2pi)

sin theta +sin 2theta+sin3theta+sin4theta=0

( sin 2 theta + 2 sin 4 theta + sin 6 theta )/(sin 4 theta + 2 sin 6 theta + sin 8 theta ) =

Solve 4sin theta sin2 theta sin4 theta=sin3 theta

Prove that ( cos theta + cos 2 theta + cos 3 theta + cos 4 theta)/(sin theta + sin 2 theta + sin 3 theta + sin 4 theta)= cot ""(5theta)/(2).

sin^(3)theta + sin theta - sin theta cos^(2)theta =