A parallel plate capcitor of capacitance C is charged to a potential V by a battery. Without disconencting the battery = distance between the plates of capacitor is triple and a dielectric medium of K = 10 is introduced between the plates of capacitor. Explain giving reasons how will the following be affected ?
(a) Capacitance of capacitor
(b) Charge on capacitor
(c ) Energy density of capacitor.

A parallel plate capacitor of capacitance C is charged to a potential V by a battery. Without disconnecting the battery, distance between the plates of capacitor is tripled and a dielectric medium of K = 10 is introduced between the plates of capacitor. Explain giving reasons how will the following be affected ? (a) Capacitance of capacitor (b) Charge on capacitor (c ) Energy density of capacitor.

Answer the following: (a) When a parallel plate capacitor is connected across a dc battery, explain briefly how the capacitor gets charged. (b) A parallel plate capacitor of capacitance 'C' is charged to 'V' volt by a battery. After some time the battery is disconnected and the distance between the plates is doubled. Now a slab of dielectric constant 1ltklt2 is introduced to fill the space between the plates. How will the following be affected ? (i) The electric field between the plates of the capacitor. (ii) The energy stored in the capacitor. Justify your answer in each case. (c) The electric potential as a function of distance 'x' is shown in the figure. Draw a graph of the electric field E as a function of x.

Explain why the capacitance of a parallel plate capacitor increases when a dielectric slab is introduced between the plates.

A parallel plate capacitor of capacitance C is charged to a potential V and then disconnected with the battery. If separation between the plates is decreased by 50% and the space between the plates is filled with a dielectric slab of dielectric constant K=10 . then

A parallel plate capacitor of capacitance C is charged to a potential V and then disconnected with the battery. If separation between the plates is decreased by 50% and the space between the plates is filled with a dielectric slab of dielectric constant K=10 . then