`inte^(cotx)/sin^2x[2 ln cosecx+sin2x]dx`

int(e^(cotx))/(sin^(2)x)("2 ln cosec x"+sin2x)dx

int(e^(cotx))/(sin^(2)x)("2 ln cosec x"+sin2x)dx

int(e^(cotx))/(sin^(2)x)("2 ln cosec x"+sin2x)dx

int e^(cot x + 2" log cosecx") dx =

int(sqrt(cotx))/(sin2x)dx-

int(sin^3x+cos^3x)/(sin^2xcos^2x)dx (A) sinx+cosx+c (B) tanx+cotx+c (C) secx-cosecx+c (D) sinx-cosx+c

Choose the correct answer int (sin^2x-cos^2x)/(sin^2x cos^2x) dx a)tanx+cotx+c b)tanx+cosecx+c c)cotx-tanx+c d) tanx+secx+c

Evaluate : int_0^(pi/2) (2 log cos x-log sin 2x)dx .

int_(0)^((pi)/(2))(2log cos x-log sin2x)dx