In an atom 2K, 8L, 8M, 2N electrons are present If m = O, s = 1/2 then find no. of `e^(Θ)` :-

In an atom which has 2K, 8L, 8M and 2N electrons in the ground state, the total number of electrons having l=1 are

In an atom which has 2K, 8L, 8M and 2N electrons in the ground state, the total number of electrons having l=1 are

An atom has 2K, 8 L, 11 M, 2N electrons, the total number of s-electrons will be

An atom has 2K, 8 L, 11 M, 2N electrons, the total number of s-electrons will be

In an atom which has 2K, 8L , 18 M and 2N electrons in the ground state . The total number of electrons having magnetic quantum number m=0 is

A neutral atom has 2K, 8L and 5M electrons, choose correct one

In an atom which has 2 K 8 L , 18 M and 2N electrons in the ground state . The total number of electrons having magnetic quantum number m=0 is

A neutral atom has 2k, 8L, 8M and 2N electrons. Find out the total number of s-electron.