" प्रश्न 6."2x^(2)+3x+1" को "x+2" से भाग दीजि। । "

int (x^6+2x^2+3x+1) dx

प्रश्न - भाग 1 |प्रश - भाग 2

lim_ (x rarr oo) ((3x ^ (2) + 2x + 1) / (x ^ (2) + x + 2)) ^ ((6x + 1) / (x + 2))

Without expanding, find the value of: (i) (x + 1)^4 - 4(x + 1)^3 (x - 1) + 6(x + 1)^2 (x - 1)^2 - 4(x + 1) (x - 1)^3 + (x -1)^4 (ii) (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4

Add 2x^(2)+3x+6, 5x+2x^(2)-6 and 4-3x

a (x) = 3x ^ (6) + 7x ^ (4) + 9x ^ (2) + 2x + 1, b (x) = 2x + 2

If x^(4) - 3x^(2) - 1 = 0 , then the value of (x^(6)-3x^(2)+(3)/(x^(2))-(1)/(x^(6))+1) is :