Find:
(i) `0.4 div 2`
(ii) `0.35 div 5`
(iii) `2.48 div 4`
(iv) `65.4 div 6`
(v) `651.2 div 4`
(vi) `14.49 div 7`
(vii) `3.96 div 4`
(viii) `0.80 div 5`

Explanation

We have,
(i) = `(4/10) div 2`
Then,
`= (4/10) xx (1/2)`
`= (2/10) xx (1/1)`
= `(2/10)`
`= 0.2`

(ii)= `(35/100) div 5`
= `(35/100) xx (1/5)`
`= (7/100) xx (1/1)`
= `(7/100)`
`=0.07`
(iii)`=(248/100) div 4`
= `(248/100) xx (1/4)`
`= (62/100) xx (1/1)`
= `(62/100)=0.62`

(iv) `= (654/10) div 6`
`=(654/10) xx (1/6)`
`= (109/10) xx (1/1)`
`= (109/10)=1.09`

(v)`= (6512/10) div 4`
`=(6512/10) xx (1/4)`
`= (1628/10) xx (1/1)`
`= (1628/10)=162.8`

(vi)`= (1449/100) div 7`
`=(1449/100) xx (1/7)`
`= (207/100)`
`=2.07`

(vii)`= (396/100) div 4`
`=(396/100) xx (1/4)`
`= (99/100)`
`=0.99`

(viii)`= (80/100) div 5`
`=(80/100) xx (1/4)`
`= (16/100)`
`=0.16`