A particle is thrown upward from ground. It experiences a constant resistive force which can produce retardation of 6 m/`sec^2` . What will be the ratio of time of descent to time of ascent (g = 10 m/`sec^2` )

A particle is thrown upwards from ground. It experiences a constant resistance force which can produce a retardation of 2 ms^-2. The ratio of time of ascent to time of descent 13 ( g = 10 ms^-2 )

A particle is thrown upwards from ground. It experiences a constant resistance force which can produce a retardation of 2 ms^-2. The ratio of time of ascent to time of descent 13 ( g = 10 ms^-2 )

A particle is thrown upwards from ground. It experiences a constant resistance force which can produce a retardation of 2 ms^-2. The ratio of time of ascent to time of descent 13 ( g = 10 ms^-2 )

A particle is thrown upwards from ground it experiences a constant resistance force which can produce retardation of 2m/s^2 The ratio of time of ascent to the time to descent is (g=10m/s^ 2)

A ball is thrown vertically upwards from the ground. It crosses a point at the height of 25 m twice at an interval of 4 secs. The ball was thrown with the velocity of

A ball is thrown vertically upwards from the ground It crosses a point at the height of 25 m twice at an interval of 4 secs . The ball was thrown with the velocity of.

A bal is thrown vertically upwards from the ground. It crosses a point at the height of 25 m twice at an interval of 4 secs. The ball was thrown with the velocity of

A particle has initial velcoity 10m//s . It moves due to constant retarding force along the line of velocity which produces a retardation of 5m//s^(2) . Then

(a) A ball is thrown vertically upward with speed 10 m//s and it returns to the ground with speed 8 m//s . Find the maximum height attained by the ball. (b) A ball is thrown vertically upward and if air resistance is half of weight of the ball, find the ratio of time of ascent and time of descent. (C) Two balls A and B (m_(A) = 2 m_(B) = 2 m) are thrown vertically upward. If air resistance is mg//2 , find ratio of maximum height attained by them.

A ball is thrown upwards from the ground. It is at a height 100 m in upward and downward journeys at time t_1 and t_2 respectively. If g = 10 m/s^(2) , then the product of t_1 . t_2 is: