Find out median , with the help of the following data :
`{:("Price Level",10-20,20-30,30-40,40-50,50-60,60-70),("Number of Commodity"," "2," "5," "8," "4," "6," "3):}`

Obtain the mean , median and mode of the following data : {:("Marks",0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Number of Students"," "5," "7," "15," "25," "20," "15," "8," "5):}

Find the mean for the following data. {:("Marks obtained",10-20,20-30,30-40,40-50,50-60,60-70),("Number of students",8,6,12,5,2,7):}

Caculate the median and mode from the following data : {:("Marks",0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Number of Students"," "2," "18," "30," "45," "35," "20," "6," "3):}

Find the first decile for the following data: {:("Size", 0.10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Frequency "," "2," "18," "30, " "45, " "35, " "20, " "6, " "3):}

Calculate median of the following of data : {:("Class Interval",0-5,5-10,10-20,20-30,30-50,50-70,70-100),("Number of Students"," "12," "15," "25," "40," "42," "14," "8):}

Find the median of the following data: {:("Class Interval",0-10,10-20,20-30,30-40,40-50),(f,6,8,5,4,7):}

In the following frequency distribution, the frequency of the class interval (40-50) is not known. Find it, if the arithmetic mean of the distribution is 52. {:("Wages(Rs.)",10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Number of Workes"," "5," "3," "4," "?," "2," "6," "13):}

Find the mean deviation about the mean for the following data: Marks obtained , 10-20, 20-30, 30-40, 40-50, 50-60, 60-70, 70-80 Number of students, 2, 3, 8, 14, 8, 3, 2

Find the mean deviation about the mean for the following data: Marks obtained,10-20,20 - 30,30-40,40-50,50-60,60-70,70-80 Number of students,2,3,8,14,8,3,2