A body of mass M splits into two parts aM and `(1-alpha)` M by an internal explosion, which generates kinetic energy T. After explosion if the two parts move in the same direction as before, their relative speed will be -

A body of mass 4m is split into two equal parts by an internal explosion which generates a kinetic energy E. If, after the explosion, the parts move in the same line as before, then what is their relative speed?

A body of mass 4m is split into two equal parts by an internal explosion which generates a kinetic energy E. If, after the explosion, the parts move in the same line as before, then what is their relative speed?

A bomb of mass 4m explodes into two parts of mass ratio 1 : 3. If k be the kinetic energy of larger part then K.E. of small part

A bomb of mass 4m explodes into two parts of mass ratio 1 : 3. If k be the kinetic energy of larger part then K.E. of small part

A projectile is moving at 20 m s^(-1) at its highest point where it breaks into equal parts due to an internal explosion. Just after explosion, one part moves vertically up at 30 ms^(-1) with respect to the ground. Then the other part will move at :

A projectile is moving at 20 m s^(-1) at its highest point where it breaks into equal parts due to an internal explosion. Just after explosion, one part moves vertically up at 30 ms^(-1) with respect to the ground. Then the other part will move at :

Relative speed of two bodies moving in same direction with speed u and v m/s: where (u>v)

A bomb of mass 3 m kg explodes into two pieces of mass m kg and m kg . If the velocity of m kg mass is 16 m / s , the total kinetic energy released in the explosion is