The parallax of a heavenly body measured from tow points diametrically opposite on equator of earth is 2.0 minute. If radius of earth is 6400 km, calculate distance of heavenly body.

The parallex of a heavenly body measured ffrom two points diametrically opposite on equater of earth is 1.0 minutes. If the radius of the earth is 6400 m, find the distance of the heavenly body from the centre of the earth in AU. Given 1 AU=1.5xx10^(11) m.

The parallax of a heavenly body measured from two points diametrically opposite on equator of Earth is 2^(1) . Calculate the distance of the heavenly body. [Given radius of the Earth = 6400 km][1" = 4.85 xx 10^(-6) rad]

Calculate the electrical capacitance of earth. The radius of earth is 6400 km.

The altitude at which the weight of a body is only 64% of its weight on the surface of the earth is (Radius of the earth is 6400 km)

A heavenly body is observed from two diametrically opposite points A and B on the earth. The angle substended at the heavenly body is 2.9 xx 10^(-4) rad. Given the diameter of Earth to be about 1.28 xx 10^(7) Compute the distance of the heavenly body from the earth.

What is the linear velocity of a body on the surface of the earth at the equator ? Given the radius of the earth is 6400 km . Period of rotation of the earth = 24 hours.