A rope of mass 250 g is 5.5 m long. It is stretched under a tensional force of 2 kg wt. If the wire is fixed at one end and is shaken by hand at the other end, what frequency will make it break into four segments ? Take, g = 980 `cm//s^(2)`.

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Convert the given values into appropriate units.
- The mass of the rope is given as 250 g, which is equivalent to 0.25 kg.
- The length of the rope is given as 5.5 m, which is equivalent to 550 cm.
- The tension force is given as 2 kg weight. To convert this into dynes (cgs unit), we use the relation \(1 \text{ kg wt} = 980 \text{ dynes}\). Therefore, the tension \(T = 2 \text{ kg} \times 980 \text{ dynes/kg} = 1960 \text{ dynes}\).

### Step 2: Calculate the mass per unit length (\(\mu\)).
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