A string of mass 2.50kg is under a tension os 200N. The length of the stretched string is 20.0m. If the transverse jerk is struck at one end of the string, how long does the disturbance take to reach the other end?

Options

A. 1 second
B. 0.5 second
C. 2 second
D. data given is insufficient

Answer

B

Explanation

`upsilon = sqrt((T)/(m)) = sqrt((200)/(2.5//20)) = sqrt((200 xx 200)/(25)) = (200)/(5)" "[m = ("mass")/("length") = (2.5)/(20)]`
or `upsilon = 40 ms^(-1)`
So time taken to travel l = 20.0 m is
`t = (l)/(upsilon) = (20.0)/(40) = 0.5` s
The correct option is (b).