A wire when stretched between two rigid supports under a tension of 60 N vibrates in p loops. The frquency at which the wire resonates is 318 Hz and the next frequency when it resonates is 390 Hz. Find the values of p and length of wire if mass per unit length of the wire is `10^(-4)` kg/m.

Explanation

To solve the problem, we need to find the values of \( p \) (the number of loops) and the length of the wire \( L \). We are given the following information:

- Tension \( T = 60 \, \text{N} \)
- Mass per unit length \( \mu = 10^{-4} \, \text{kg/m} \)
- First frequency \( f_1 = 318 \, \text{Hz} \)
- Second frequency \( f_2 = 390 \, \text{Hz} \)

### Step 1: Write the frequency equations
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