The fundamental note of a stretched wire is 128 Hz. If we increase the length by 20 cm keeping the stretching force constant, the frequency becomes 110 Hz. What will be the original length of the wire ?

Explanation

To solve the problem, we need to use the relationship between the frequency of a stretched wire and its length. The fundamental frequency \( f \) of a stretched wire is given by the formula:

\[ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} \]

where:
- \( f \) is the frequency,
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