Two waves are represented by the equations
`y_(1)=asin(omegat+kx+0.57)m` and
`y_(2)=acos(omegat+kx)`m,
where x is in metres and t is in seconds. The phase difference between them is

Options

A. 1.0 radian
B. 1.25 radian
C. 1.57 radian
D. 0.57 radian

Answer

A

Explanation

`y_(1) = a sin (omega t + kx + 0.57)`
`y_(2) = a cos (omega t + kx) = a sin (omega t + kx + pi//2)`
Phase difference `= (pi)/(2) - 0.57`
= 1.57 radian - 0.57 radian
= 1 radian