When two tuning forks (fork `1` and fork `2`) are sounded simultaneously, `4` beats per second are heard. Now some tape is attached on the prong of the fork `2`. When the tuning fork are sounded again, `6` beats per second are heard. If the frequency of fork `1` is `200 Hz`, then what was the original frequency of fork `2` ?

Options

A. 204 Hz
B. 196 Hz
C. 202 Hz
D. 200 Hz

Answer

B

Explanation

Given, `f_(1) = 200 Hz, f_(1) - f_(2) = +- 4` Hz
Since mass of second tuning fork increses so frequency of fork 2 `(f_(2))` decreases therefore, beats increase so `f_(1) gt f_(2)`
`f_(2) = f_(1) - 4 = 200 - 4 = 196` Hz