The equation of a wave on a string of linear mass density `0.04 kg m^(-1)` is given by `y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))]`. The tension in the string is :

Options

A. 6.25 N
B. 4.0 N
C. 12.5 N
D. 0.5 N

Answer

A

Explanation

`y = 0.02 (m) sin [2pi ((t)/(0.04(s)) - (x)/(0.50(m)))]`
This equation is compared with
`y = A sin [2pi ((x)/(lambda) - (t)/(T))]`
we get `lambda` = 0.50 m and T = 0.04 s
Tension in the string
`T = mu v^(2) = mu ((lambda)/(T))^(2)`
`= 0.04 xx ((0.5)^(2))/((0.04)^(2)) = 6.25` N