When two sounds of frequencies 512 Hz and 516 Hz reach our ear simultaneously then number of beats formed are

Options

A. 4
B. 2
C. 6
D. 8

Answer

To find the number of beats formed when two sounds of frequencies 512 Hz and 516 Hz reach our ears simultaneously, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Frequencies**:
- Let \( f_1 = 512 \, \text{Hz} \) (the frequency of the first sound)
- Let \( f_2 = 516 \, \text{Hz} \) (the frequency of the second sound)

2. **Use the Beat Frequency Formula**:
- The formula for the number of beats formed per second (also known as beat frequency) is given by:
\[ \text{Number of beats} = |f_2 - f_1| \]

3. **Calculate the Difference**:
- Substitute the values of \( f_1 \) and \( f_2 \) into the formula:
\[ \text{Number of beats} = |516 \, \text{Hz} - 512 \, \text{Hz}| \]

4. **Perform the Calculation**:
- Calculate the absolute difference:
\[ \text{Number of beats} = |4 \, \text{Hz}| = 4 \, \text{Hz} \]

5. **Conclusion**:
- Therefore, the number of beats formed is \( 4 \, \text{Hz} \).

### Final Answer:
The number of beats formed is **4 beats per second**.

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