The displacements of two travelling waves are represented by the equations as :
`y_(1) = a sin (omega t + kx + 0.29)m and y_(2) = a cos (omega t + kx)m` here x, a are in m and t in s, `omega` in rad. The path difference between two waves is `(x xx 1.28) (lambda)/(pi)`. Find the value of x.
`

Explanation

To solve the problem, we need to find the value of \( x \) given the equations of two traveling waves and the path difference between them. Let's break down the solution step by step.

### Step 1: Identify the equations of the waves
The two waves are given by:
1. \( y_1 = a \sin(\omega t + kx + 0.29) \)
2. \( y_2 = a \cos(\omega t + kx) \)

### Step 2: Convert \( y_2 \) to sine form
...