`18g` of glucose (molar mass `180g "mol"^(-1)`) is present in `500CM^(3)` of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

Answer

0.2M, density of the solution in needed to calculate molality of the solution.

Explanation

Moles of glucose ` = (18)/(180) = 0.1 mol`
Molarity `= (0.1)/(500) xx 1000 = 0.2 M`
Density of solution in needed to calculate the molality of the solution .