Calculate the molarity and mole fraction of the solute in aqueous solution containing `3.0 g` of urea per `250gm` of water (Mol. Wt. of urea = 60)

Answer

Molality = 0.2 m

Explanation

Moles of urea ` = (3)/(60) = 0.05`
Molality ` = (0.05)/(250) xx 1000 = 0.2m`
Moles of water ` = (250)/(18) = 13.89`
Moles of water solute ` = (0.05)/(13.89 + 0.05) = 0.0036`