Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:

Answer

2.29 m

Explanation

2.05 M acetic acid solution menas 2.05 moles of acetic acid are present in 100 mL of solution .
Mass of solution ` = 1000 xx 1.02 = 1020 g`
Mass of 2.05 moles of `CH_(3) COOH`
` = 60 xx 2.05 = 123 g`
Mass of water ` = 1020 - 123 = 897 g`
Molality ` =(2.05)/(897) xx 1000 = 2.29m`