Concentrated `HNO_(3)` is 69% by mass of nitric acid. Calculate the volume of the solution which contains `23 g` of `HNO_(3)`. (Density of concentrated `HNO_(3)` solution is `1.41 g ml^(-1))`

Answer

`23.6 cm^(2)`

Explanation

69% `HNO_(3)` means 69 g of `HNO_(3)` is present in 100 g of solution .
Vol.of solution ` = (100)/(1.41) = 70.92 mL`
69g of `HNO_(3)` is present in solution ` = 70.92 mL`
23 g of `HNO_(3)` is present in solution ` = (70.92)/(69) xx23 = 23.64 mL`