At a certain temperature , the vapour pressure ( in mm Hg) of `CH_(3)OH` and `C_(2) H_(5)OH` solution is represented by P = 119 x + 135 where x is the mole fraction of `CH_(3)OH` . What are the vapour pressure of pure components at this temperature ?

Answer

`p_((CH_(3)OH)) = 254 mm Hg`
`p_((C_(2)H_(5)OH)) 135 mm Hg`

Explanation

For `CH_(3) OH ,` x = 1
` therefore P = 119+135 = 245 mm H`
For `C_(2)H_(5)OH , x = 0`
`therefore P = 119 xx 0+135 = 135 mm Hg`