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The vapour pressure of water is 12.3 kPa...

The vapour pressure of water is `12.3 kPa` at `300 K`. Calculate vapour pressure of `1` molal solution of a solute in it.

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The correct Answer is:
12.08 kPa
Mole fraction of solute ` =(1)/(1+1000//18) = 0.0177`
` (123-p_(A))/(12.3) = 0.0177 " "therefore " "p_(A) = 12.08` kPa
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