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The boiling of a solution containing 1...

The boiling of a solution containing 1.5 g of dichlorobenzene in 100 g of benzene was higher by `0.268^(@)C` . Calculate the molar mass of dichlorobenzene (`k_(b)` for benzene 2.62 degree/molal)

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To solve the problem of calculating the molar mass of dichlorobenzene based on the boiling point elevation, we can follow these steps: ### Step 1: Identify the given data - Mass of dichlorobenzene (solute, \( W_B \)) = 1.5 g - Mass of benzene (solvent, \( W_A \)) = 100 g - Elevation in boiling point (\( \Delta T_b \)) = 0.268 °C - Boiling point elevation constant for benzene (\( K_b \)) = 2.62 °C/m ### Step 2: Write the formula for boiling point elevation The formula for boiling point elevation is given by: \[ \Delta T_b = K_b \times m \] Where \( m \) is the molality of the solution. The molality can be calculated using: \[ m = \frac{W_B}{M_B \times W_A} \] Where: - \( W_B \) = mass of solute (dichlorobenzene) - \( M_B \) = molar mass of solute (dichlorobenzene, which we need to find) - \( W_A \) = mass of solvent (benzene) ### Step 3: Substitute the expression for molality into the boiling point elevation formula Substituting the expression for molality into the boiling point elevation formula gives: \[ \Delta T_b = K_b \times \frac{W_B}{M_B \times W_A} \] ### Step 4: Rearrange the formula to solve for \( M_B \) Rearranging the equation to isolate \( M_B \): \[ M_B = \frac{K_b \times W_B \times 1000}{\Delta T_b \times W_A} \] ### Step 5: Substitute the known values into the equation Now we substitute the values we have: - \( K_b = 2.62 \, \text{°C/m} \) - \( W_B = 1.5 \, \text{g} \) - \( \Delta T_b = 0.268 \, \text{°C} \) - \( W_A = 100 \, \text{g} \) Substituting these values: \[ M_B = \frac{2.62 \times 1.5 \times 1000}{0.268 \times 100} \] ### Step 6: Perform the calculations Calculating the numerator: \[ 2.62 \times 1.5 \times 1000 = 3930 \] Calculating the denominator: \[ 0.268 \times 100 = 26.8 \] Now, divide the numerator by the denominator: \[ M_B = \frac{3930}{26.8} \approx 146.6 \, \text{g/mol} \] ### Conclusion Thus, the molar mass of dichlorobenzene is approximately **146.6 g/mol**. ---

To solve the problem of calculating the molar mass of dichlorobenzene based on the boiling point elevation, we can follow these steps: ### Step 1: Identify the given data - Mass of dichlorobenzene (solute, \( W_B \)) = 1.5 g - Mass of benzene (solvent, \( W_A \)) = 100 g - Elevation in boiling point (\( \Delta T_b \)) = 0.268 °C - Boiling point elevation constant for benzene (\( K_b \)) = 2.62 °C/m ...
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